Question

prove that the given figure​

Answer 1

Step-by-step explanation:

In triangle ABC ,

AC > AB ( Given)

So , we know that the angle in opposite of larger side is larger .

Hence , Angle ABD > Angle ACD

( 1 / 2 ) of Angle ABD > ( 1 / 2 ) of Angle ACD

Hence ,

Angle PBD > Angle PCD ( given that PB and PC are bisectors )

Now , we get that

Angle PBD > Angle PCD

But , side in opposite of larger angle is larger , So ,

Side opposing PBD > Side opposing PCD ,

PC > PD .

Hence proved .

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