prove that the given value is = 13/33
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(3^30+3^29+3^28) /3^31+3^30-3^29
3^28(3^2+3+1) /3^28(3^3+3^2-3)
3^28 gets cancelled
(9+3+1) /27+9-3)
13/33
hence proved
hope it helps
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