Physics, asked by vishalkumarvirat30, 1 year ago

Prove that the gravitational force on earth is 9.8N.

Answers

Answered by Anonymous
1
HEY...

g =GM /R^2

g = \frac{6.67 \times {10}^{ - 11} \times 6 \times {10}^{24}}{ {(6.64 \times {10}^{6} )}^{2} } \\ \\ g = 9.8m {s}^{ - 2}
Answered by ashutosh416988
0

Mass of earth m1 =6 × 1024 kg

Mass of the object m2 = 1 kg

Radius of the earth =6.4 × 106 m

Universal gravitational constant G = 6.67 x 10-11 Nm2kg-2

By applying universal law of gravitation: - F = (G m1 m2/r2)

= (6.67 x 10-11 x 6 × 1024 x 1)/ (6.4 × 106)2

F = 9.8 N

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