Question

Prove that the gravitational force on earth is 9.8N.

Answer 1

✨✌⭐Here is the answer⭐✌✨

✨⭐The force of gravitational attraction on a mass of 1 kg on the Earth is 9.8 N. Another way of putting that is that the gravitational field strength on the surface of the Earth is 9.8 N/kg⭐✨

✨✌⭐hope it helps⭐✌✨

Answer 2

$\huge{\bold{\red{\star{\pink{Heya!}}}}}$

We know that the gravitational force acting between two bodies having mass is given by

$F=\frac{GMm}{{r}^{2}}$ - equation(1)

Also we know by second law of motion

F = ma - equation(2)

$ma =\frac{GMm}{{r}^{2}}$

$a =\frac{GM}{{r}^{2}}$

This gives acceleration due to gravity on any planet

For earth we have

Radius (r) = $6.3781×{10}^{6} m$

Mass (M)= $5.972 × {10}^{24} kg$

Gravitational constant (G) = $6.673×{10}^{-11}{N m}^{2} {kg}^{-2}$

By putting the values of G, M and r

We get, $g= 9.810665m/{s}^{2}$

$g= 9.8m/{s}^{2}$