prove that the increase in the Kinetic energy of the body equal to work done by the force on the body
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We know that
W=Fs where W is work done and F is force and s is displacement. Here there is a condition that initial velocity is 0. So
W=mas (F=ma)
W=m*(V2−u2)/2(V2−u2)/2
W=mv2/2v2/2
This work done is stored as Kinetic Energy. So now we know that
KE=mv2/2v2/2
Now again we assume a condition where u is not 0. Following above steps we reached.
W=m*(V2−u2)/2(V2−u2)/2
W=mv2/2−mu2/2mv2/2−mu2/2
W=Final kinetic energy - Initial kinetic energy.
W=Fs where W is work done and F is force and s is displacement. Here there is a condition that initial velocity is 0. So
W=mas (F=ma)
W=m*(V2−u2)/2(V2−u2)/2
W=mv2/2v2/2
This work done is stored as Kinetic Energy. So now we know that
KE=mv2/2v2/2
Now again we assume a condition where u is not 0. Following above steps we reached.
W=m*(V2−u2)/2(V2−u2)/2
W=mv2/2−mu2/2mv2/2−mu2/2
W=Final kinetic energy - Initial kinetic energy.
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