Question

Prove that the interior angle of a regular five sided polygon (pentagon) is three times the exterior angle of a regular decagon

Answer 1

Answer:

$sum \: of \: all \: interior \: angle \: of \: pentagon \: = 540 \\ a \: interior \: angle = \frac{540}{5} = 108 \\ sum \: of \: all \: exterior \: angle \: of \: decagon = 360 \\ a \: exterior \: angle \: = \frac{360}{10} = 36 \\ 36 \times 3 = 108 \\ prooveddddddddddddddddddd$

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