Question

prove that the interior angle of a regular hexagon are equal to 3 times the exterior angle of a decagon.​

Answer 1

Answer:

Step-by-step explanation:

A pentagon has sides so interior angle=(n-2)180/n where n=5

=108 degrees

Sum of external angles of any polygon is 360 degrees

So 360/10=36 degrees

3(36 degree)=108 degree

Hence Proved

Answer 2

a Pentagon has sides so interior angle

= (n-2)180/n where n=5

=180⁰

sum of external angles of any polygon is 360⁰

so, 360/10=36

3(36⁰)=108⁰

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