Question

prove that the interior angle of a regular pentagon is 3 times the exterior angle of a regular decagon​

Answer 1

Answer:

One interior angle of a penagon =(n−2)×

n

180

where n=5

=(5−2)×

5

180

=108

Exterior angle of any polygon is 360.

One exterior angle of decagon =

10

360

=36

108=3×36

Therefore it's proved that one interior angle of pentagon is three times the exterior angle of decagon.

Step-by-step explanation:

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