prove that the interior angle of a regular pentagon is three times the exterior angle of a regular decagon.
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A pentagon has sides so interior angle=(n-2)180/n where n=5
=108 degrees
Sum of external angles of any polygon is 360 degrees
So 360/10=36 degrees
3(36 degree)=108 degree
Hence Proved
=108 degrees
Sum of external angles of any polygon is 360 degrees
So 360/10=36 degrees
3(36 degree)=108 degree
Hence Proved
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