Question

Prove that the interior angle of a regular pentagon is three times the exterior angle of a regular decagon.... The Correct answer will be marked as the Brainliest

Answer 1

Step-by-step explanation:

one interior angle of a Pentagon =(n-2)×180/n

where n = 5

(5-2)×180/5 =108

sum of exterior angles of any polygon= 360

so , one exterior angle of a decagon =360/10=36

108=3×36

hence proved

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