Question

prove that the interior angle of a regular pentagon is three times the exterior angle of regular decagon​

Answer 1

Step-by-step explanation:

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Answer 2

One interior angle of a Pentagon =(n−2)× 180/n

where n=5

=(5−2)× 180/5

=108

Exterior angle of any polygon is 360.

One exterior angle of decagon = 360/10

=36

and 108=3×36

hence prooved