prove that the interior angle of a regular pentagon is three times the exterior angle of decagon
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A pentagon has sides sointerior angle=(n-2)180/n
where n=5Interior
Angle = 108 deg Sum ofexternal angles of any polygon is 360 degrees
So, 360/10=36 deg
3(36 degree)=108 degree
Hence, Proved.
where n=5Interior
Angle = 108 deg Sum ofexternal angles of any polygon is 360 degrees
So, 360/10=36 deg
3(36 degree)=108 degree
Hence, Proved.
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0
let me know answer it would be twice not thrice
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