prove that the interior angles regular angles of a pentagon is 3 times the exterior angles of a regular decagon
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Now, each exterior angle of a decagon will be equal to 360n, here n = 10. So, we get an exterior angle of a regular decagon as, 36010=36∘. So, we get that the interior angle of a regular five-sided polygon (pentagon) is three times the exterior angle of a regular decagon. Hence proved.
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