Question

prove that the internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle

Answer 1

your answer is in the image

Answer 2

very simple logic behind it.. let suppose a triangle ABC where AB and AC are sides and BC is base.. a bisector from A is drawn to BC let suppose that point is P now there are two triangles ABP and ACP... now simple use pythagorus or value substitution and prove both are equal to each other