prove that the kinetic energy of a freely falling object on reaching the ground is nothing but the transformation of its initial potential energy.
pls give answer . I have to sleep
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Answer:
Total energy at initial position = K.E + P.E = 0 + mgh
Total energy when it reaches the ground = K.E + P.E = 0.5mv^2 + 0
Velocity when it reaches the ground = sqrt(2gh)
Substitute velocity in total energy equation
Total energy when it reaches the ground = 0.5mv^2 = 0.5m * 2gh = mgh
We found that total energy when it reaches the ground = Total energy at initial position.
In other words, kinetic energy with which it hits the ground is the transformation of its initial potential energy.
Ok nancy you can sleep now bye
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- Thus, it can be concluded that the kinetic energy of a freely falling object on reaching the ground is nothing but the transformation of its initial potential energy. This is because mass of the object can never be 0. Hence, when the object has zero momentum, its kinetic energy is also zero.
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