Question

prove that the length of tangents drawn from an external point to a circle are equal​

Answer 1

Answer:

here there s ur answer kk

Answer 2

Step-by-step explanation:

Let the two concentric circles centred at point O.And let PQ be the chord of the larger circle which touches the smaller circle at point A.Therefore, PQ is tangent to the smaller circle.

OA perpendicular PQ( As OA is the radius of the circle)

Applying Pythagoras theorem in ∆OAP, we obtain

OA^2+AP^2=OP^2

3^2+AP^2=5^2

AP^2=9-25

AP=√16

AP=4

In ∆OPQ,

Since OA perpendicular PQ,

AP=AQ( Perpendicular from the centre of the circle bisects the chord)

Therefore,PQ=2AP = 2×4=8

Therefore, the length of the chord of the larger circle is 8 cm.

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