prove that the length of tengent from an external point are equal.
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Answer:
The attached figure shows two tangents, SK and SR drawn to circle with center O from an external point K.
To prove that: SK=RK
Proof:
Normal and tangent at a point on the circle are perpendicular to each other.
∠OSK=∠ORK=90o
Using Pythagoras Theorem,
OK2=OS2+SK2(i)
OK2=OR2+RK2(ii)
Subtracting (ii) from (i),
OK2−OK2=OS2+SK2−OR2−RK2
⟹SK2=RK2∵OS=OR
SK=RK
Hence, proved
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