Question

Prove that the line drawn through the centre of a circle to bisect a chord is perpendicular to the chord. . OR If the diagonals of a parallelogram are equal, then show that it is a rectangle​

Answer 1

Answer:

1st Case :

Here AP=PB

OA=OB (radius)

OP=OP (common)

⇒△POA≅△POB

⇒∠APO=∠BPO,

But ∠APO+∠BPO=180°

⇒2∠APO=90°

⇒∠APO=∠BPO=90°

solution

Step-by-step explanation:

Please draw the diagram where u first draw a circle, then draw chord (which is not the radius of the circle) and name it AB then from the centre of the circle O draw a perpendicular line to the mid point of the chord and then mark the point P. At last join AO and BO.

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