prove that the line joining the mid point of a rectangle forms a rambous
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Step-by-step explanation:
Let ABCD be a rhombus and P, Q, R and S be the mid-points of sides AB, BC, CD and DA respectively.
In ABD and BDC we have.
From (i) and (ii) we get.
PQRS is a ||gm
As diagonals of a rhombus bisect each other at right angles.
Since SP||BD, PQ||AC and AC BD.
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