Question

prove that the line of centers of two intersecting circle subtends equal angles at the two points of intersection. ​

Answer 1

Answer:

In ∆ ACB and ∆ ADB

AC = AD ( Radii of circle with center A )

BC = BD ( Radii of circle with center B )

AB = AB ( common )

so,by SSS criterion of congruence

∆ ACB perpendicular to ∆ ADB

⇒ACB = ADB

hope this helps you

Answer 2

Answer:

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