Question

prove that the line passing through (-2,6) and (4,8) is perpendicular to the line (8,12) and (4,24)

Answer 1

Given

(x1,y1)1=(-2,6)

(x2,y2)=(4,8)

(x3,y3)=(8,12)

(x4,y4)1=(4,24)

By using slope formula

M1=y2-y1/x2-x1

M2=y4-y3/x4-x3

Therefore

m1=8-6/4+2=1/3

m2=24-12/4-8=-1/3

Since

M1xm2=-1

The lines are perpendicular to each other

Answer 2

Hope it helps you....

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