PROVE THAT THE LINE SEGMENT JOINING THE MID POINTS OF TWO SIDES OF A TRIANGLE IS PARALLEL TO THE THIRD SIDE AND IS HALF OF IT.
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2
its thales theorem or bpt theorem, check it in your maths book from triangles lesson
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Let in triangle ABC ,
D & E are the mid points of side AB & AC respectively.
A midpoint divides a line segment into two equal parts.so D divides AB in the ratio 1:1 , as well as E also divides the AC in the ratio 1:1
=> So it clear that, Point D & E divides the two sides in the same ratio.
so by Converse of BPT.
=> DE is parallel to BC .
>> DE||BC
:-)Hope it helps u.
D & E are the mid points of side AB & AC respectively.
A midpoint divides a line segment into two equal parts.so D divides AB in the ratio 1:1 , as well as E also divides the AC in the ratio 1:1
=> So it clear that, Point D & E divides the two sides in the same ratio.
so by Converse of BPT.
=> DE is parallel to BC .
>> DE||BC
:-)Hope it helps u.
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