prove that the line segment joining the midpoint of the side of a triangle divide it into four congruent Triangle
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Let the main triangle ABC
D be the mid point of AB there for AD=DB
E be the mid point of AC there for AE=EC
F be the mid point of BC there for BF=FC
by the fig we can see that line segment DF is parallel to the line EC so DF=EC
similarly EF=AD
DE=FC
by the definition of congruent triangles theorem proved . " :)
D be the mid point of AB there for AD=DB
E be the mid point of AC there for AE=EC
F be the mid point of BC there for BF=FC
by the fig we can see that line segment DF is parallel to the line EC so DF=EC
similarly EF=AD
DE=FC
by the definition of congruent triangles theorem proved . " :)
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