Prove that the line segment joining the midpoints of the sides of a triangle divide it into four congruent triangles.
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Solution: Let the main triangle ABC
D be the mid point of AB there for AD=DB
E be the mid point of AC there for AE=EC
F be the mid point of BC there for BF=FC
by the fig we can see that line segment DF is parallel to the line EC so DF=EC
similarly EF=AD
DE=FC
by the definition of congruent triangles theorem proved . "
D be the mid point of AB there for AD=DB
E be the mid point of AC there for AE=EC
F be the mid point of BC there for BF=FC
by the fig we can see that line segment DF is parallel to the line EC so DF=EC
similarly EF=AD
DE=FC
by the definition of congruent triangles theorem proved . "
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Answered by
68
Hope this will help
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rakeshmohata:
thanks for the brainliest one
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