prove that the line through 0, 0 and 2, 3 is parallel to the line through 2, - 2 and 6, 4
Answers
Find the gradient of the line that passes through (0,0) and (2,3)
Gradient = (Y2 - Y1)/(X2 - X1)
= (3 - 0)/(2 - 0)
= 3/2
Find the gradient of the line that passes through (2, -2) and (6, 4)
Gradient = (Y2 - Y1)/(X2 - X1)
= (4 + 2) / (6 - 2)
= 6/4
= 3/2
Since both the gradient are the same
⇒ The lines are parallel
Given:
Line 1: ( 0, 0 ) ( 2, 3)
Line 2: ( 2, -2 ) ( 6, 4 )
To find:
To prove both the lines are parallel.
Condition:
The gradient of both the lines should be same.
Solution:
For line 1:
(0,0) and (2,3)
Gradient = ( Y2 - Y1 ) / ( X2 - X1 )
Gradient = ( 3 - 0 ) / ( 2 - 0 )
Gradient for line 1 = 3/2
For line 2:
( 2, -2 ) and ( 6, 4 )
Gradient = ( Y2 - Y1 ) / ( X2 - X1 )
Gradient = (4 + 2) / (6 - 2)
Gradient for line 2 = 3/2
Gradient of line 1 and line 2 = 3/2
As the gradient of both the lines are the same, the lines are parallel.
Hence, proved.