Question

prove that the log2 is an irrational ​

Answer 1

Answer:

The function 2^x is one-to-one, which means if 2^p = 2^q for any values p and q, then p = q. Since p = 0, this means q = 0. ... This contradiction means the assumption that log 2 is rational must be false. So log 2 is irrational.

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