Question

prove that the loss in weight of a body when immersed wholly or partially in a liquid is equal to the buoyant force(or upthrust) and this loss is because of the difference in pressure exerted by liquid on the upper and the lower surfaces of the submerged part of the body

Answer 1

According to Archimedes principle, “A body immersed in a liquid loses weight by an amount equal to the weight of the liquid displaced.” and “When a body is immersed in a liquid, an upward thrust, equal to the weight of the liquid displaced, acts on it.”

So, when a solid is fully immersed in a liquid, it loses weight which is equal to the weight of the liquid it displaces. The more the density of the liquid in which the solid is immersed, the less is the weight of the liquid displaced on immersing the solid.

The loss in weight of the body = Weight of water displaced by the body = Buoyant Force or up-thrust exerted by water on the body.

The volume of the water displaced = Volume of the body immersed in water.

Answer 2

According to Archimedes principle, “A body immersed in a liquid loses weight by an amount equal to the weight of the liquid displaced.” and “When a body is immersed in a liquid, an upward thrust, equal to the weight of the liquid displaced, acts on it.”

So, when a solid is fully immersed in a liquid, it loses weight which is equal to the weight of the liquid it displaces. The more the density of the liquid in which the solid is immersed, the less is the weight of the liquid displaced on immersing the solid.

The loss in weight of the body = Weight of water displaced by the body = Buoyant Force or up-thrust exerted by water on the body.

The volume of the water displaced = Volume of the body immersed in water

Explanation: