Question

Prove that the maximum horizontalal range is four times the maximum height attained by the projectile. When lire at an inclined so as to have maximum horizontal range.

Answer 1

for this max. tetha should be 45 °

u^2sin^2 45° /2g = u^2sin 90° /g

u^2 /4g = u^2 /g

4 hmax = R