Prove that the measure of two angles of a triangle
If equal, the lengths of their opposite arms will be equal.
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Step-by-step explanation:
in ∆ABC
construct the altitude AD
Now,
in ∆ABD &∆ACD
AD=AD. (common)
angle ADB= angle ADC. ( both 90)
angle ABD= angle ACD. (given)
therefore ,∆ABD &∆ACD are congruent by RHS
So, AB=AC. (by CPCT)
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