Question

Prove that the midpoint of the hypotenuse of a right triangle is equidistant from its vertices

Answer 1

Step-by-step explanation:

Let D be the midpoint of AC.

We know that the circumcentre and mid-point of a right angle triangle lie in the same point

Therefore D is the circumcentre of triangle ABC

SINCE AD=CD

SINCE AD=CD=BD

Therefore, the mid-point of the hypotenuse of a right angle triangle is equidistant from its vertices.

Answer 2

a round solid figure, or its surface, with every point on its surface equidistant from its centre.