Prove that the nth term of an A.P. cannot be n2 + 2. Justify your answer
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an=n2+2
d= an-an-2
d= (n2-2)-[(n2-1)2+2]
d=n2-2-n2+4n-2-2
d=4n-2
since the common difference depends upon
n and not constant , n2+2 cannot be nth term of an AP.
it will help you
d= an-an-2
d= (n2-2)-[(n2-1)2+2]
d=n2-2-n2+4n-2-2
d=4n-2
since the common difference depends upon
n and not constant , n2+2 cannot be nth term of an AP.
it will help you
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