prove that the numbers 2 rootover 3-7
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Answered by
5
Answer:
23–7
Now, let us assume 23–7 be a rational number, ‘r’
So,23–7=r
23=r+7
3=(r+7)/2
We know that ‘r’ is rational, ‘(r+7)/2’ is rational, so ‘3’ is also rational.
This contradicts the statement that 3 is irrational.
So, 23–7 is an irrational number.
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Answered by
1
Step-by-step explanation:
So,23–7=r
23=r+7
3=(r+7)/2
We know that ‘r’ is rational, ‘(r+7)/2’ is rational, so ‘3’ is also rational.
This contradicts the statement that 3 is irrational.
So, 23–7 is an irrational number.
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