prove that the opposite angles of an isosceles trapezium are supplementary
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Answered by
347
In an isosceles trapezium AB is parallel to DC and the alternate interior angles are supplementary. So, the angles ∠A and ∠D are supplementary.which means
∠A + ∠D = 180
Similarly, ∠B and ∠C are supplementary.
so, ∠B + ∠C = 180
Since the trapezium is the isosceles trapezium, the base angles are equal. ∠C = ∠DSo by subsituting the anles we get
∠A + ∠C = 180
∠B + ∠D = 180
so the opposite angles are also supplementary
∠A + ∠D = 180
Similarly, ∠B and ∠C are supplementary.
so, ∠B + ∠C = 180
Since the trapezium is the isosceles trapezium, the base angles are equal. ∠C = ∠DSo by subsituting the anles we get
∠A + ∠C = 180
∠B + ∠D = 180
so the opposite angles are also supplementary
Answered by
108
Given: An isosceles Trapezium ABCD
To prove: Opposite angles are supplementary
Proof : AB||CD. Therefore, angle A + angle D =180°
Angle a = angle b (As the Trapezium is isosceles)
Angle b + angle d = 180°
Therefore, angle a + angle c = 180°
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