Question

Prove that: The opposite angles of two equal sides of an isosceles triangle are the same.​

Answer 1

Answer:

Refer the above attachment , it will be helpful 4 u .

Answer 2

Answer:

The opposite angles of two equal sides of an isosceles triangle are the same.​

Step-by-step explanation:

Given: An isosceles triangle.

To find opposite angles of two equal sides are equal.

Consider the figure given below.

In triangle ABC consider sides AC=BC, <ACD=,BCD.

Now in $\triangle \mathrm{ACD}$ and $\triangle \mathrm{BCD}$ we have,

$\mathrm{AC}=\mathrm{BC} \text { (Given) }$$\mathrm{AC}=\mathrm{BC} \text { (Given) }$

$\angle \mathrm{ACD}=\angle \mathrm{BCD}$ (By figure)

  $C D=C D$ (Common)

Thus, by SAS congruence criterion $\triangle \mathrm{ACD} \cong \triangle \mathrm{BCD}$.

So, $\angle \mathrm{CAB}=\angle \mathrm{CBA}($ By CPCT)

Hence the opposite angles of two equal sides of an isosceles triangle are the same.​

#SPJ3