Question

prove that the opposite angles two equal sides of a triangle are equal​

Answer 1

Step-by-step explanation:

let us take triangle ABC where AB=AC

• To prove=∠b=∠c
• construction=draw AD perpendicular to BC,

If AD is perpendicular to BC

Then BD=CD

• Proof=In triangle ABD and triangle ACD

= AB=AC[Given]

= AD=AD[Common]

= BD=CD[from construction]

so,by sss rule

Triangle ABD≅triangle ACD

By CPCT, ∠B=∠C

Hence proved