Prove that the pair of straight lines joining the origin to the point of intersection of the curve (x ^ 2)/(a ^ 2) + (y ^ 2)/(b ^ 2) = 1 by the straight line lx + my + n = 0 , are at right angle if 1/(a^2) + 1/(b^2) = 1/(n^2) (l^2+m^2)
Answers
Step-by-step explanation:
The coordinates of the points in which the straight line meets the curve will satisfy both equations (1) and (2) and hence they satisfy the following equation.
x
2
+
y
2
−
2
(
h
x
+
k
y
)
(
x
2
h
+
y
2
k
)
+
(
h
2
+
k
2
−
a
2
)
(
x
2
h
+
y
2
k
)
2
=
0
⇒
4
h
2
k
2
(
x
2
+
y
2
)
−
4
h
k
(
h
x
+
k
y
)
(
k
x
+
h
y
)
+
(
h
2
+
k
2
−
a
2
)
(
h
x
+
k
y
)
2
=
0
)
⇒
4
h
2
k
2
(
x
2
+
y
2
)
−
4
h
k
(
h
k
x
2
+
h
k
y
2
+
(
h
2
+
k
2
)
x
y
)
+
(
h
2
+
k
2
−
a
2
)
(
k
x
+
h
y
)
2
=
0
.
⇒
4
h
2
k
2
(
x
2
+
y
2
)
−
4
h
2
k
2
(
x
2
+
y
2
)
−
4
h
k
(
h
2
+
k
2
)
x
y
+
(
h
2
+
k
2
−
a
2
)
(
k
2
x
2
+
h
2
y
2
)
+
(
h
2
+
k
2
−
a
2
)
(
2
h
k
x
y
)
=
0
.
⇒
4
h
2
k
2
(
x
2
+
y
2
)
−
4
h
2
k
2
(
x
2
+
y
2
)
−
4
h
k
(
h
2
+
k
2
)
x
y
+
(
h
2
+
k
2
−
a
2
)
(
k
2
x
2
+
h
2
y
2
)
+
(
h
2
+
k
2
−
a
2
)
(
2
h
k
x
y
)
=
0
.
This is the equation of the pair of straight lines joining the origin to the points of intersection of the given lines and the curve. They will be at right angle if the sum o bef the coefficients of
x
2
and
y
2
is zero.
Imposing this condition we get
(
h
2
+
k
2
−
a
2
)
(
h
2
+
k
2
)
=
0
As
(
h
2
+
k
2
)
≠
0
We get
h
2
+
k
2
−
a
2
=
0
⇒
h
2
+
k
2
=
a
2