Question

prove that the parallelogram Circumscribing a circle is a rohmbus​

Answer 1

Answer:

Given ABCD is a ||gm such that its sides touch a circle with centre O. We know that, tangents to a circle from an exterior point are equal in length. In rhombus, it is not necessary that diagonals are equal. If they are equal, then rhombus is considered as a square whose diagonals are always equal.