Prove that the parallelogram circumscribing a circle
is a rhombus.
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Answer:
tangents are equal to each other of a circle wali theoram use karo
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Step-by-step explanation:
OP perpendicular AB and OS perpendicular AD
In ∆OPB &∆OSD,ang OPB=ang OSD [each 90°]
OB=OD
OP=OS. [radii]
∆OPB=~∆OSD. [RHS]
PB=SD. [CPCT] 1
AP=AS. 2
Add 1&2
AP+PB=AS+DS
AB=AD
AB=BC=CD=DA
:.|| gm ABCD is arhombus
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