Prove that the parallelogram circumscribing a circle is a rhombus.
Answers
Answer:
open the pic
Step-by-step explanation:
reason:- tangents to the same circle are equal to each other
We have given that = ABCD Is a paralogram .
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus -
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus - Step-by-step explanation:
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus - Step-by-step explanation:
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus - Step-by-step explanation: AP = AQ
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus - Step-by-step explanation: AP = AQ BR = BO
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus - Step-by-step explanation: AP = AQ BR = BO DS
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus - Step-by-step explanation: AP = AQ BR = BO DS RC = CS
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus - Step-by-step explanation: AP = AQ BR = BO DS RC = CS AP + BR + PD + RC = AQ + BQ + DS + SC
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus - Step-by-step explanation: AP = AQ BR = BO DS RC = CS AP + BR + PD + RC = AQ + BQ + DS + SC AD + BC = AB + DC
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus - Step-by-step explanation: AP = AQ BR = BO DS RC = CS AP + BR + PD + RC = AQ + BQ + DS + SC AD + BC = AB + DC AD + AD = AB + AB
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus - Step-by-step explanation: AP = AQ BR = BO DS RC = CS AP + BR + PD + RC = AQ + BQ + DS + SC AD + BC = AB + DC AD + AD = AB + AB AD = AB
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus - Step-by-step explanation: AP = AQ BR = BO DS RC = CS AP + BR + PD + RC = AQ + BQ + DS + SC AD + BC = AB + DC AD + AD = AB + AB AD = AB AD = AB = BC = DC
We have given that = ABCD Is a paralogram . To prove that ABCD is a rhombus - Step-by-step explanation: AP = AQ BR = BO DS RC = CS AP + BR + PD + RC = AQ + BQ + DS + SC AD + BC = AB + DC AD + AD = AB + AB AD = AB AD = AB = BC = DC ABCD IS A ROMBUS