Question

Prove that the parallelogrms lying in the same base and same parallels have the same area

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Theorem: Triangles having the same base and equal areas lie between the same parallels.
GIVEN : ABCD is a parallelogram, AC is diagonal

TO PROVE : ar (Δ ABC ) = ar (Δ CDA ) 

proof:in triangles ABC , CDA 

AB = CD (opposite sides of a parallelogram )

BC = DA (opposite sides of a parallogram )

AC = AC (common ) 

therefore Δ ABC Δ CDA (S-S-S congruency)

there fore Δ ABC = Δ CDA (if two triangles are congruent then their areas are equal ).