Prove that the path of a projectile is parabolic. Also derive the expressions for maximum height and horizontal range of a projectile.
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Show that the path of a projectile is a parabola
Then, vertical component of u, uy=ucosθ
Horizontal component of ux=usinθ
X=uxt.
Again, y=uyt+1/2ayt2.
The range (R) of the projectile is the horizontal distance it travels during the motion. Using this equation vertically, we have that a = -g (the acceleration due to gravity) and the initial velocity in the vertical direction is usina (by resolving). Hence: y = utsina - ½ gt2
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