Question

prove that the path of projectile is parabolic

Answer 1

eq of path of projectile is s=ucos@ -gt2/2

if two projectiles are projected from horizontal ground with different initial velocity and angle....both these quantities are known then at any time t

coordinates of A,  S1=(UacosA)t i - gt2/2 j

coordinates of B, S2=(UbcosB)t i - gt2/2j

 coordinates of A wrt to B is S2-S1=t(UacosA-UbcosB)i + 0 j
       Xi + Yj = kt i + 0j                                     (UacosA-UbcosB = constant=k)

  ie X=kt  is a straight line     ....


        
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Hope it helps you..