Question

Prove that the path of projectile is parabolic

Answer 1

x =
x = ucosθ.t
t = x/ucosθ------(1)

Again, y =
y = usinθt - 1/2gt²
Put equation (1) here,
y = usinθ × x/ucosθ - 1/2g × x²/u²cos²θ
= tanθx - 1/2gx²/u²cos²θ

This equation is similar to Standard equation of parabola y = ax² + bx + c her, a, b and c are constant

So, A projectile motion