prove that the perimeter of a triangle is greater than the sum of its three medians
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Step-by-step explanation:
WE KNOW THAT THE SUM OF ANY TWO SIDES OF A TRIANGLE IS GREATER THAN TWICE THE MEDIAN DRAWN TO THE THIRD SIDE. AB+AC>2AD;. AB+BC>2BE & BC+AC>2CF. Hence, the perimeter of a triangle is greater
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Answer:
WE KNOW THAT THE SUM OF ANY TWO SIDES OF A TRIANGLE IS GREATER THAN TWICE THE MEDIAN DRAWN TO THE THIRD SIDE. AB+AC>2AD;. AB+BC>2BE & BC+AC>2CF. Hence, the perimeter of a triangle is greater than the sum of its three medians.
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