prove that the perpendicular at the point of contact to the tangent to the circle passes through the centre
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Answer:
Given : let us assume a circle with centre O
and AB a tangent which intersecting circle at point P
To prove : OP perpendicular AB
Proof :
Tangent of circle is a perpendicular to radius at point of contact
hence, OP perpendicular AB
so, angle OPB = 90 ° . ........ (1)
let us assume some point X
such that, XP perpendicular AB
hence, angle XPB = 90° . ...... (2)
from 1 and 2
angle OPB = angle XPB = 90°
which is possible only if line XP passes through O
hence, perpendicular to tangent passes through centre
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