prove that the perpendicular bisectors of a chord of a circle always passes through the centre
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in triangle cad and triangle cbd
AD=dB. given
angle CDA= angle CDA. CD perpendicular to AB
CD=CD. reflexive property
triangle CDA = triangle CDB by SAS
CA=CB. by cpct
Q is center of circle the center of the circle is only a point within the circle that has only points on the circumference equal point on that
AD=dB. given
angle CDA= angle CDA. CD perpendicular to AB
CD=CD. reflexive property
triangle CDA = triangle CDB by SAS
CA=CB. by cpct
Q is center of circle the center of the circle is only a point within the circle that has only points on the circumference equal point on that
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