Question

prove that the perpendicular bisectors of two non-parallel chords of a circle intersect at its centre​

Answer 1

Answer:

here is the answer for your question

hope it helps you

Answer 2

The prove that the perpendicular bisector of two non parallel chords of a circle intersect  at its centre.

Step-by-step explanation:

Given:

       ⇒  ∠ORP = ∠ORQ

       ⇒ QR = RP

 Now, from question,

         

               ⇒    ∠ORP = ∠ORQ ( given above)

              ⇒    ∠OPR = ∠OQR (given above)

             ⇒   OR = OR  (common according to figure)

            So, by side-side-side, ΔOPR ≅ ΔOQR.

Hence,  OP = OQ, which means they are radii of the circle as they pass from the centre O to the corners.