Prove that the point (-2,-11) is equidistant from the two points (-3,7) and (4,6)
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Answered by
26
Hello users....
We have to prove that
point A (-2,-11) is equidistant from the two points B (-3,7) and C(4,6)
Solution :-
Using distance formula
AB = √{-3-(-2)}² + { 7-(-11)}²
=> √(-1)² +18² = √1+ 324
= √325
Now
AC = √{4-(-2)}² + {6-(-11)}²
=> √6² +17² = √36 + 289
=> √ 325
Hence
AB =AC
⭐⭐ Hope it helps ⭐⭐
We have to prove that
point A (-2,-11) is equidistant from the two points B (-3,7) and C(4,6)
Solution :-
Using distance formula
AB = √{-3-(-2)}² + { 7-(-11)}²
=> √(-1)² +18² = √1+ 324
= √325
Now
AC = √{4-(-2)}² + {6-(-11)}²
=> √6² +17² = √36 + 289
=> √ 325
Hence
AB =AC
⭐⭐ Hope it helps ⭐⭐
Answered by
15
I solved the problem. You can see the pic I uploaded
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