prove that the points (0,1,2) (2,-1,3) and( 1,-3,1) from an isosceles right angled triangle
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Answered by
1
Step-by-step explanation:
AB=
(2−0)
2
+(−1−1)
2
+(3−2)
2
=3
BC=
(2−1)
2
+(−1+3)
2
+(3−1)
2
=3
CA=
(1−0)
2
+(−3−1)
2
+(1−2)
2
=3
2
Clearly, AB=BC and AB
2
+BC
2
=AC
2
.
Hence, triangle ABC is an isosceles right-angled triangle.
Answered by
1
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