Prove that the points (0,9) (b/2,a/2) and (b,0
are collinear
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Answer:
Step-by-step explanation:
Area of triangle = 1/2[x1(y2-y3)+x2(y3+y1)+x3(y1-y2)
0 =0(a/2-0)+b/2(0-9)+b(9-a/2)
0=[9-a]
a=9
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